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-3x^2+261x-2700=0
a = -3; b = 261; c = -2700;
Δ = b2-4ac
Δ = 2612-4·(-3)·(-2700)
Δ = 35721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{35721}=189$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(261)-189}{2*-3}=\frac{-450}{-6} =+75 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(261)+189}{2*-3}=\frac{-72}{-6} =+12 $
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